(9^2)=3*(3+x)

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Solution for (9^2)=3*(3+x) equation: 



(9^2)=3(3+x)

We move all terms to the left:

(9^2)-(3(3+x))=0

We add all the numbers together, and all the variables

-(3(x+3))+9^2=0

We add all the numbers together, and all the variables

-(3(x+3))+81=0



We calculate terms in parentheses: -(3(x+3)), so:

3(x+3)

We multiply parentheses

3x+9

Back to the equation:

-(3x+9)



We get rid of parentheses

-3x-9+81=0

We add all the numbers together, and all the variables

-3x+72=0

We move all terms containing x to the left, all other terms to the right

-3x=-72

x=-72/-3

x=+24

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